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(x+10)(x+3)-(x+8)(x-1)=(x-2)(x-1)-x^2
We move all terms to the left:
(x+10)(x+3)-(x+8)(x-1)-((x-2)(x-1)-x^2)=0
We multiply parentheses ..
-((+x^2-1x-2x+2)-x^2)+(x+10)(x+3)-(x+8)(x-1)=0
We calculate terms in parentheses: -((+x^2-1x-2x+2)-x^2), so:We get rid of parentheses
(+x^2-1x-2x+2)-x^2
We add all the numbers together, and all the variables
-1x^2+(+x^2-1x-2x+2)
We get rid of parentheses
-1x^2+x^2-1x-2x+2
We add all the numbers together, and all the variables
-3x+2
Back to the equation:
-(-3x+2)
3x+(x+10)(x+3)-(x+8)(x-1)-2=0
We multiply parentheses ..
(+x^2+3x+10x+30)+3x-(x+8)(x-1)-2=0
We get rid of parentheses
x^2+3x+10x+3x-(x+8)(x-1)+30-2=0
We multiply parentheses ..
x^2-(+x^2-1x+8x-8)+3x+10x+3x+30-2=0
We add all the numbers together, and all the variables
x^2-(+x^2-1x+8x-8)+16x+28=0
We get rid of parentheses
x^2-x^2+1x-8x+16x+8+28=0
We add all the numbers together, and all the variables
9x+36=0
We move all terms containing x to the left, all other terms to the right
9x=-36
x=-36/9
x=-4
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